Molar mass of NaOH = 40 g/mole
First we have to calculate the mass of NaOH.
As, 1L of solution contains 4 g of NaOH
So, 0.05 L of solution contains 4 x 0.05 = 0.2 g of NaOH
The mass of NaOH = 0.2 g
Now we have to calculate the ***** of NaOH.
The ***** of NaOH = Mass of NaOH/ Molar mass of NaOH = (0.2 g)/(40g/mole) = 0.005 mole
The ***** of NaOH = 0.005 mole
Now we have to calculate the ***** of HCl.
The balanced chemical reaction will be,
NaOH + HCl ---> NaCl + H2O
From the balanced reaction we conclude that
As, 1 mole of NaOH neutralizes 1 mole of HCl
So, 0.005 mole of NaOH neutralizes 0.005 mole of HCl
The ***** of HCl = 0.005 mole
Now we have to calculate the volume of HCl.
As we know that at STP,
1 mole of HCl contains 22.4 L volume of HCl
So, 0.005 mole of HCl contains 22.4 x 0.005 = 0.112L = 112 ml volume of HCl
Therefore, the volume of HCl gas at STP will be, 0.112 L or 112 ml.
