Correct answer is (A) 87
As the maximum volume of airbag will remain same irrespective of temperature hence to fill me bag at 298 K.
V = 44.8 L
T = 298 K
P = 1 atm
n (of N2) = 1.83
***** of NaN3 required = 2/3 x 1.83 = 1.22 mole
mass of NaN3 required = 1.22 × 65 = 79.4 g
⇒ So it should be bonus.
Comment : If we consider that airbag will contain same mole at both temperature (273 K & 298 K) (i.e. assuming volume expansion at bag with temperature)
So ***** of N2 at STP = 2 (T = 273 K)
***** of N2 at 298 K & 1 atm = 2
***** of NaN3 reqd. = 2/3 x 2 = 4/3
Mass of NaN3 required = 4/3 x 65 = 84 g.
So (A) can be considered with the above unjustified assumptions.