Question

∫sinx(logx)dx is equal to

(A) x/2[sin(lnx) + cos(lnx)] + c

(B) x/2[cos(lnx) - sin(lnx)] + c

(C) x/2[sin(lnx) - cos(lnx)] + c

(D) x[sin(lnx) - cos(lnx)] + c

Answer 1

Answer is (C) x/2[sin(lnx) - cos(lnx)] + c