+2 votes
in JEE by kratos

The equation (bar)zz + (bar)az + (bar)az + b = 0, b ∈ R represents a circle, if

(A) |a|2 = |b|2

(B) |a|2 ≥ b

(C) |a|2 < b

(D) of these

1 Answer

+6 votes
by kratos
 
Best answer

Correct option**(B) |a|2 ≥ b**

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