Question

If f(x) = asin(πx/2) + b, f1(1/2) = √2 and ∫f(x)dx for x ∈ [0, 1] = 2a/π, then

(A) a = π/2, b = π/2

(B) a = 2/π, b = 3/π

(C) a = 0, b = -4/π

(D) a = 4/π, b = 0

Answer 1

Answer is (D) a = 4/π, b = 0

Therefore,

b = 0

The only choice with a = 4/π