+2 votes
in JEE by kratos

Let f:[1/2, 1] →R(the set all real numbers) be a positive, non-constant and differentiable function such that f'(x) < 2f(x) and f(1/2) = 1. Then the value of ∫f(x)dx for x ∈ [1/2, 1] the interval

(A) (2e - 1, 2e)

(B) (e - 1, 2e - 1)

(C) ((e - 1)/2, e - 1)

(D) (0, (e - 1)/2)

1 Answer

+2 votes
by kratos
 
Best answer

Answer is (D) (0, (e - 1)/2)

We have

which implies that ye−2x is a decreasing function.

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