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in JEE by kratos

Solve: p2 + 2py cot x = y2.

1 Answer

+5 votes
by kratos
 
Best answer

The given equation is

p2 + 2py cot x = y2 ...(i)

(p + y cot x)2 = y2(1 + cot2x)

(p + y cot x)2 = y2cosec2 x

(p + y cot x) = ± y cosec x

p = y(cosec x – cot x) ...(ii)

and p = – y(cosec x – cot x) ...(iii)

From Eq. (ii), we get,

dy/dx = y(cosec x – cot x)

dy/y = (cosec x – cot x)dx

dy/y = ((1 – cos x)/sin x)dx

dy/y = tan(x/2) dx

Integrating, we get

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