+1 vote
in JEE by kratos

The differential equation of the family of parabolas with focus at the origin and the x-axis as axis is

(A) y(dy/dx)2 + 4x(dy/dx) = 4y

(B) - y(dy/dx)2 = 2x(dy/dx) - y

(C) y(dy/dx)2 + y = 2xy(dy/dx)

(D) y(dy/dx)2 + 2xy(dy/dx) + y = 0

1 Answer

+3 votes
by kratos
 
Best answer

Answer is (B) - y(dy/dx)2 = 2x(dy/dx) - y

Equation of family of parabolas with focus at (0, 0) and the x-axis as axis is y2 = 4a(x + a). (1)

On differentiating Eq. (1) with respect to x,

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