Let A = {x I x is a prime number and x < 30}. The number of different rational numbers whose numerator and denominator belong to A is
(A) 90
(B) 180
(C) 91
(D) of these
Correct option**(C) 91**
A = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29}.
A rational number is made by taking any two in any order. So, the required number of rational numbers is (including 1)
10P2 + 1 = 10!/8! + 1 = 90 + 1 = 91