8 litre of H2 and 6 litre of Cl2 are allowed to react to maximum possible extent. Find out the final volume of reaction mixture. Suppose P and T *** constant throughout the course of reaction -
(A) 7 litre
(B) 14 litre
(C) 2 litre
(D) of these.
Correct Answer is: (B) 14 litre
H2 + Cl2 → 2 HCl
| Volume before reaction | 8 lit | 6 lit | 0 | | Volume after reaction | 2 | 0 | 12 |
∴ Volume after reaction
= Volume of H2 left + Volume of HCl
formed = 2 + 12 = 14 lit
