Correct Answer is: (C) (3, 4)
Let point P(x1 , y1 )
x1 – y1 + 3 = 0
C.O.C.w.r.t. (x1 , y1 ) of y2 = 4ax
yy1 = 4(x + x1 )
y(x1 + 3) = 4x + 4x1
yx1 + 3y – 4x – 4x1 = 0
(3y – 4x) + x1 (y – 4) = 0
L1 + λL2 = 0
L1 = 0 & L2 = 0
3y = 4x y = 4
x = 3
point (3, 4)