Correct Answer is: (B) 0.1575 gm
Per mole of given acid C2O42– present = 1 mole
∴ C2O4 2– → CO2 + 2e
∴ x factor for H2C2O4 . 2H2O as a reducing agent = 2
∴ equiv. wt. = 126/2 = 63
250 ml of centinormal solution
= 250/100 x 10-3 equiv.
wt. of H2C2O4 . 2H2O required
= 250/100 x 10-3 × 63 gm = 0.1575 gm