The subset P, formed first, may contain none, one, two,… or all elements of A. P and Q have no common elements. Any element x of A has one of the four possibilities.
x ∈ P; x ∈ Q
x ∈ P; x ∉ Q
x ∉ P; x ∈ Q
x ∉ P; x ∉ Q
Case 2, 3, 4 correspond to P and Q having no common element. Hence, the probability that this element x is not in P or not in Q is 3/4. The same is true of the other elements.
Hence, the probability is
nCn(3/4)n(1/4)0