Spin magnetic moment of Xn+ (Z = 26) is √24 B.M. Hence number of unpaired electrons and value of n respectively are :
(A) 4, 2
(B) 2, 4
(C) 3, 1
(D) 0, 2
Correct Answer is: (A) 4, 2
Magnetic moment = √n(n + 2) = √24 B.M.
∴ No. of unpaired electron = 4.
X26 : 1s2 2s22p63s23p63d64s2.
To get 4 unpaired electrons, outermost configuration will be 3d6 .
∴ No. of electrons lost = 2 (from 4s2 ).
∴ n = 2.