Two adjacent sides of a parallelogram ABCD are given by AB = 2i + 10j + 11k and AD = –i + 2j + 2k.

Question 1

Two adjacent sides of a parallelogram ABCD are given by AB = 2i + 10j + 11k and AD = –i + 2j + 2k. The side AD is rotated by an acute angle a in the plane of the parallelogram so that AD becomes AD'. If AD' makes a right angle with the side AB, the cosine of the angle a is given by

Question 2

Answer is (b) √17/9

Explanation:

Let θ be the angle between AB and AD.

kratos · Answer 1 · 2020-04-10T11:39:04+0000

Answer is (b) √17/9

Explanation:

Let θ be the angle between AB and AD.

Two adjacent sides of a parallelogram ABCD are given by AB = 2i + 10j + 11k and AD = –i + 2j + 2k.

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1 Answer

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Two adjacent sides of a parallelogram ABCD are given by AB = 2i + 10j + 11k and AD = –i + 2j + 2k.

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1 Answer

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