Le f(x) = {(sin(tan-1x) + sin(cot-1x)}2 - 1 where |x| > 1 and dy/dx = 1/2 d/dx(sin-1f(x)). If y(√3) = π/6 then y(-√3) =
(1) 5π/6
(2) - π/6
(3) π/3
(4) 2π/3
Answer is (2) - π/6