Question

A lift can hold 2000 kg, friction is 4000 N and power provided is 60 HP. (1 HP = 746 W) Find the maximum speed with which lift can move up.

(1) 1.9 m/*

(2) 1.7 m/*

(3) 2 m/*

(4) 1.5 m/*

Answer 1

Answer is (1)

4000 × V + mg × V = P

{60 x 7446}/{4000 + 20000} = V

V = 1.86 m/ ≈ 1.9 m/