A stone is thrown horizontally with a velocity ν from the top of the tower of height h. what is the change in velocity when the some reaches the ground.
(a) [u2 + 2gh]1/2.
(b) [u2 - 2gh]1/2.
(c) √2gh
(d) [u2 + 2gh]1/2 – u
Answer is (c) √2gh
Initial velocity = iu
Final velocity = iu + j √2gh,
Hence ∆ν = √2gh.