Question

If momentum is increased by 20% then K.E increases by

(A) 44%

(B) 55%

(C) 66%

(D) 77%

Answer 1

Answer is (A) 44%

K = p2/2m

K’ = [(1200/100)P]2/2m = 1.44 p2/2m = 1.44 K

∆K = K’ – K = 0.44 K = 44 % K