A force of 10i - 3j + 6k acts on a body of 5 kg and it displace it from 6i + 5j - 3km to 10i – 2j +7km. The work done is
(1) 121 J
(2) 0
(c) 100 J
(4) none of these.
Answer is (1) 121 J
W = F.d = (10i - 3j + 6k).(10i – 2j + 7k - 6i - 5j + 3k) = (10i - 3j + 6k).(4i – 7j + 10k)
= 40 + 21 + 60 = 121 J
