+3 votes
in Class 12 by kratos

A loop of radius 2 m weights 100 kg. It rolls along a horizontal floor so that its centre of mass has a speed of 20 cm/*. How much work is done to stop it?

1 Answer

+1 vote
by kratos
 
Best answer

R = 2 m, M = 100 kg

v = 20 cm/ = 0.2 m/

Total energy of the loop

Work required to stop the hoop = total energy of the hoop

= 100 (0.2)2 = 4

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