Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of 72 kmh-1 in the same direction, with A ahead of B. The driver of B decides to overtake A and accelerates by 1 ms-2. If after 50 *, the guard of B Just brushes past the driver of A, what was the original distance between them?
Initially,
Relative Acceleration a = 1 ms-2
v0 = 72 kmh-1 = 72 × (5/18) ms-1
= 20 ms-1
Relative displacement = x
Relative velocity initially = V0 – V0 = 0
X = 1/2 at2
= 1/2 × 1 × 502 = 1250 m
Original distance between the trains = 1250 m.
