The mean and variance of a binomial distribution are 12 and 3 respectively. Find the probability distribution.
For binomial distribution,
mean = nP = 12 and variance = npq = 3
12q = 3
q = 1/4
∴ P = 1 - q = 1 - (1/4) = 3/4
and n.p = 12
n.(3/4) = 12
n = 16
∴ Binomial distribution is
(P + q)n = ((3/4) + (1/4))16
