+2 votes
in Class 11 by kratos

Solve: 3x + 8 > 2, when

(i) x is an integer

(ii) x is a real number.

1 Answer

+6 votes
by kratos
 
Best answer

Given: 3x + 8 > 2

⇒ 3x > 2 – 8 = – 6

∴ x > - 6/3 = - 2

(i) When x ∈ Z, solution set = {-1, 0, 1, 2, 3,…}

(ii) When x∈M, solution set = (-2, ∞).

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