Solve: 3x + 8 > 2, when
(i) x is an integer
(ii) x is a real number.
Given: 3x + 8 > 2
⇒ 3x > 2 – 8 = – 6
∴ x > - 6/3 = - 2
(i) When x ∈ Z, solution set = {-1, 0, 1, 2, 3,…}
(ii) When x∈M, solution set = (-2, ∞).