Question

A rectangular conductor LMNO is placed in a uniform magnetic field of 0.5T. The field is directed perpendicular to the plane of the conductor. When the arm MN of length of 20cm is moved towards left with a velocity of 10ms–1, calculate the emf induced in the arm. Given the resistance of the arm to be 5Ω(assuming that other arms are of negligible resistance) find the value of the current in the arm.

Answer 1

Induced emf in a moving rod in a magnetic field is given by
ε = – Blv
Since the rod is moving to the left so
ε = + Blv
= 0.5 x 0.2 x 10
= 1v
Current in the rod I = ε/R = 1/5 = 0.2A