Express the following in a + ib form [(1/3 + i7/3) + (4 + i1/3)] - (- 4/3 + i)
(1/3 + 4/1 + 4/3) + i(7/3 + 1/3 - 1/1) = ((1 + 12 + 4)/3) + i((7 + 1 - 3)/3)
= 17/3 + i(4/3) = a + ib
