Question

Which term of A.P 4 is (5(1/3) - 4), 6(2/3) .... is 104?

Answer 1

In given A.P: a = 4, d = 51/3 – 4 = 16/3 – 4 = 4/3

Let nth term be 104 = Tn = a + (n – 1)d

⇒ 4 + (n – 1)4/3 = 104

⇒ 12 + 4n – 4 = 312 ⇒ 4n – 4 = 312

⇒ 4n = 312 – 8

⇒ 4n = 304

∴ n = 76