Question

The second and fifth term of GP are 3 and 81/8 respectively. Find the GP

Answer 1

Given T2 = ar = 3, T5 = ar4 = 81/8

T5/T2 = ar4/ar = r3 = (81/8)/3 = 27/8

∴ r = 3√(33/23) = 3/2

If ar = 3 ⇒ a. 3/2 = 3 ⇒ a = 2

G.p is 2, 3, 9/2, …….