+2 votes
in Class 11 by kratos

Ten years ago the average age of the family of 4 members was 24 years. Two **** have been born. The average age of the family is same to day. Find the present age of two **** assuming that the ****’* age differ by 2 years.

1 Answer

+4 votes
by kratos
 
Best answer

10 year ago x = 24, n = 4

∴ x = 24 × 4 = 96 year

If 10 years ago, total age of 4 member = 96 year

total age of member now = (96 + 10 × 4) year = 136 year

Total age of 6 member = 74 × 6 = 144 year

i.e., Sum of age of 2 **** = 144 – 136 = 8 year

so x + x + 2 = 8 = x = 3 year

∴ The ages of **** 3 and 4 year.

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