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Solve: sin2x dx
+3
votes
asked
Mar 23, 2019
in
JEE
by
kratos
Solve: sin2x dx
limits
class-11
jee
differential equations
jee mains
class-12
trigonometric functions
continuity
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1
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+5
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answered
Feb 4, 2021
by
kratos
Best answer
= -1/2[-1, - 1] = 2/2 = 1
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