Factorize:
y3 + 125
= y3 + 53 [a3 + b3 = (a + b)(a2 –ab + b2)]
= (y + 5)(y2 − 5y + 52)
= (y + 5)(y2 − 5y + 25)
Therefore, y3 + 125 = (y + 5)(y2 − 5y + 25)
