Question

Calculate emf of the cell:

Zn()|Zn2+(aq)||Fe2+(aq)|Fe() if Zn2+ = -0.76v EFe2+ = -0.44v

Answer 1

Zn()|Zn2+(aq)||Fe2+(aq)|Fe();

E°cell = -0.44 - (-0.76)

= 0.32V