Question

Let E1={x∈R: x≠1 and x/x-1>0}

and E2={x∈E1 :sin-1(loge(x/x-1)) is a real number}

(Here, the inverse trigonometric function sin 1 x assumes values in [-π/2,π/2].)

Let f : E1 → R be the function defined by f (x)=loge(x/x-1)

and g : E2 → R be the function defined by g(x)=sin-1(loge(x/x-1)).

The correct option is :

Answer 1

Answer**:A**

Solution: