Question

The point on the curve x2 = 2y which is nearest to the point (0, 5) is

(A) (2, √2, 4)

(B) (2, √2, 0)

(C) (0, 0)

(D) (2, 2)

Answer 1

Answer is (A)

Let p(x, y) be the nearest point to the point (0, 5)