(i) Given as 5x + 7y + 2 = 0 and 4x + 6y + 3 = 0
Above equation can be written as
|A| = 30 - 28 = 2
Therefore, the above system has unique solution given as
X = A-1B
Suppose Cij be the cofactor of aij in A
So, x = 9/2 and y = -7/2
(ii) Given as 5x + 2y = 3
3x + 2y = 5
Above equation can be written as
Here
|A| = 10 - 6 = 4
Therefore, the above system has unique solution given as
X = A-1B
Suppose Cij be the cofactor of aij in A
So, x = -1 and y = 4