+3 votes
in Class 12 by kratos

Deduce the condition for balance of a wheat stone’ bridge using Kirchhoff’ rules.

1 Answer

+4 votes
by kratos
 
Best answer

Wheatstone’ bridge is a device used to determine unknown resistance. It consists of 4 arms of resistances P, Q, R & , a galvanometer of resistance ‘G’ & a battery with plug key. Let ‘I’ be the main current & splits into branch current I1 & I2 respectively.

Applying KVL to the mesh ABDA

I1P + IgG – I2R = 0 ………..(1)

parallelly to the mesh BCDB

(I1 – Ig)Q – (I2+ Ig)* – IgG = O ….(2)

The wheatstone bridge is said to be balanced when no current flowing through the galvanometer.

i.e., Ig = 0

eqn (1) I1P – I2R = 0

I1P – I2R …………(3)

eqn (2) is I1Q – I1S = 0

I1Q – I2S ………….. (4)

This is the balanced condition of Wheatstone bridge.

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