+1 vote
in Class 10 by kratos

Find the HCF of the pairs of numbers 475 and 495.

1 Answer

+5 votes
by kratos
 
Best answer

By applying Euclid’* Division lemma on 495 and 475 we get,

495 = 475 x 1 + 20.

Since remainder ≠ 0, apply division lemma on 475 and remainder 20

475 = 20 x 23 + 15.

Since remainder ≠ 0, apply division lemma on 20 and remainder 15

20 = 15 x 1 + 5.

Since remainder ≠ 0, apply division lemma on 15 and remainder 5

15 = 5 x 3+ 0.

Therefore, H.C.F. of 475 and 495 is 5.

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