Given,
f(x)= x3 + 13x2 + 32x + 20
And, -2 is one of the zeros. So, (x + 2) is a factor of f(x),
Performing division algorithm, we get
⇒ f(x) = (x2 + 11x + 10)( x + 2)
So, putting x2 + 11x + 10 = 0 we can get the other 2 zeros.
⇒ (x + 10)(x + 1) = 0
∴ x = -10 or -1
Hence, all the zeros of the polynomial are -10, -2 and -1.