Question

Calculate the EMF of the cell for the reaction

Mg() + 2Ag+(aq) → +Mg2+(aq) + 2Ag( )

Given: E0Mg2+/Mg = -2.37V

E0Ag+/Ag = -0.80V

[Mg2+] = 0.001M;

[Ag+] = 0.0001 M

log 105 = 5

Answer 1

ECell = Eright – Eleft

= 0.80 – (-2.37 V)

= 3.17 V