Question

Find the following products:

4/3a (a2 + b2 – 3c2)

Answer 1

Given,

4/3a (a2 + b2 – 3c2)

= 4/3a (a2 + b2 – 3c2)

= (4/3a × a2) + (4/3a × b2) – (4/3a × 3c2)

= 4/3a3 + 4/3ab2 – 4ac2