+3 votes
in Physics by kratos

The neutron separation energy is defined as the energy required to remove a neutron from the nucleus. Obtain the neutron separation energies of the nuclei ({20}^{41}Ca,\, {13}^{27}Al) from the following data:
(m({20}^{40}Ca)= 39.962591u)
(m(
{20}^{41}Ca)= 40.962278u)
(m({13}^{26}Al)= 25.986895u)
(m(
{13}^{27}Al)= 26.981541u)

1 Answer

+3 votes
by kratos
 
Best answer

For (_{20}^{41}Ca) Nucleus:

= Neutron separation energy

...