An ideal gas (γ= 1.67) is taken through the process abc shown in figure (27-E3). The temperature at the point a is 300 K. Calculate (a) the temperatures at b and c, (b) the work done in the process, (c) the amount of heat supplied in the path ab and in the path be and (d) the change in the internal energy of the gas in the process.
(a) For a, b ’V’ is constant
(b) Work done = Area enclosed under the graph 50 cc × 200 kpa = 50 × 10–6 × 200 × 103 J = 10 J (c) ‘Q’ Supplied = nCvdT
Now, ΔU = Q – w = Heat supplied – Work done = (24.925 + 14.925) – 1 = 29.850
