From 3rd & 6th column we conclude that
p ↔ q (p ↔ q) ∧ (q ↔ p)
(ii) p → (q → r) and (p → q) → r
From last two columns we conclude that p → (q → r) and (p → q) → r are not logically equivalent
(iii) (p ∧ ~q) ∨ q and p ∨ q
From last two columns we conclude (p ∧ ~q) ∨ q p ∨ q.
(iv) p↔ q and (~ p ∨ q) ∧ ( ~q ∨ p)
From 3rd and 8th columns we conclude that p ↔ q ≡ (~ p ∨ q) ∧ (~q ∨ p)
(v) P ∧ q and (p → ~q)
Column 3 and column 6 are identical :
∴ They are logically equivalent
(vi) ~ (p ↔ q ) and (p ∧ ~q) ∨ (q ∧~p)
4th & 5th columns are identical
∴ they are logically equivalent
(vii) p ∨ (q ∧ r) and (p ∨ q)∧ (p ∨ r)
5th column & 8th columns are identical
∴ p∨ (q∧r) = (p ∨ q)∧ (p ∨ r)