Given, A.P. 3, 8, 13,…
Here, a = 3 and d = a2 – a1 = 8 – 3 = 5
We know that, nth term an = a + (n – 1)d
Required to check nth term an = 302
a + (n – 1)d = 302
3 + (n – 1)5 = 302
3 + 5n – 5 = 302
5n – 2 = 302
5n = 304
⇒ n = 304/5, which is not a whole number.
Therefore, 302 is not a term in the A.P.
