Given as the difference between the two acute angles of a right-angled triangle is 2π/5 radians.
As we know that π rad = 180° ⇒ 1 rad = 180°/π
Also given
2π/5
(2π/5 × 180/ π)°
By substituting the value of π = 22/7
(2 × 22/(7 × 5) × 180/22 × 7)
(2/5 × 180)°
72°
Suppose one acute angle be x° and the other acute angle be 90° – x°.
Now,
x° – (90° – x°) = 72°
2x° – 90° = 72°
2x° = 72° + 90°
2x° = 162°
x° = 162°/2
x° = 81° and
90° – x° = 90° – 81°
= 9°
Thus, the angles are 81° and 9°