Question

The angle of elevation of a tower from a point on the same level as the foot of the tower is 30°. On advancing 150 meters towards the foot of the tower, the angle of elevation of the tower becomes 60°. Show that the height of the tower is 129.9 metres.

Answer 1

Given,

The angle of elevation of top tower from first point D, α = 30°

On advancing through D to C by 150 m, then CD = 150 m

Angle of elevation of top of the tower from second point C, β = 60°

Let height of tower AB = H m

Representing the above data in form of figure then it form a figure as shown with ∠B = 90°

Therefore, the height of the tower = 129.9 m