Let AB be the T.V tower of height ‘h’ m on the bank of river and ‘D’ be the point on the opposite side of the river. An angle of elevation at the top of the tower is 30°
Let AB = h and BC = x
And, given CD = 20 m
From fig. we have
In ΔACB
h = 10√3 m
And,
x = h/√3
x = 10√3/ √3
x = 10
Therefore, the height of the tower is 10√3 m and width of the river is 10 m.