+3 votes
in JEE by kratos

A charged particle is accelerated through a potential difference of 12kV and acquires a speed of 1.0 x 106m/*. It is then injected perpendicularly into a magnetic field of strength 0.2T. Find the radius of the circle described by it.

1 Answer

+3 votes
by kratos
 
Best answer

V = 12KV E = V/I

Now, F = qE = qV/I or a = F/m = qV/ml

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