Resolve the quadratic trinomials into factors:
3x2 + 22x + 35
We have,
The coefficient of x2 is 3
The coefficient of x is 22
Constant term is 35
So, we express the middle term 22x as 15x + 7x
3x2 + 22x + 35 = 3x2 + 15x + 7x + 35
= 3x (x + 5) + 7 (x + 5)
= (3x + 7) (x+ 5)
