Given fraction defective = 0.05, and sample size 8. Write down the control limits for number of defectives
Given: P1 = 0.05, n = 8,
Here Q1 = 1 – P1 = 1 – 0.05 = 0.95
The control limits for number of defectives np/d – chart (When standards are given) are:
C.L = np1 =8 × 0.05 = 0.4
